alleryA solid object floats with 80 % of its volume submerged in water (ρ_water = 1000 kg m⁻³). The density of the object is:
A200 kg m⁻³
B800 kg m⁻³
C1000 kg m⁻³
D1200 kg m⁻³
Answer & Solution
Correct answer: B. 800 kg m⁻³
1. By Archimedes', weight of object = weight of displaced water.
2. ρ_obj · V · g = ρ_water · 0.80 V · g.
3. ρ_obj = 0.80 × 1000 = 800 kg m⁻³.
_Source: syllabus Physics Ch 9 §9.3 Archimedes' Principle (floating bodies)_
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