The height to which a liquid rises in a capillary tube of radius r is (with surface tension T, contact angle θ, density ρ):
Ah = 2 T cosθ / (r ρ g)
Bh = T cosθ / (r ρ g)
Ch = T sinθ / (r ρ g)
Dh = ρ g r / (2 T cosθ)
Answer & Solution
Correct answer: A. h = 2 T cosθ / (r ρ g)
1. Balance upward surface-tension force around the meniscus circumference with weight of the lifted liquid.
2. Upward force = T cosθ · 2π r.
3. Weight of lifted column = ρ g h · π r².
4. Equate: h = 2 T cosθ / (r ρ g).
5. So h is inversely proportional to r — narrower tubes lift higher (mercury depresses, since cosθ < 0).
_Source: syllabus Physics Ch 9 §9.8 Capillary Rise_
Keep practising Mechanical Properties of Solids and Fluids
Browse all Mechanical Properties of Solids and Fluids questions for AP Intermediate 1st Year, or explore more Physics topics.
Related questions
Poiseuille's law gives the volume flow rate Q of a viscous fluid through a horizontal pipeA solid object floats with 80 % of its volume submerged in water (ρ_water = 1000 kg m⁻³). Two soap bubbles of radii R₁ < R₂ are connected by a tube. Air flows:A liquid emerges from a hole at depth h below the free surface of a large open tank. The eThe excess pressure inside a spherical liquid drop of radius R and surface tension T is:Surface tension T of a liquid is best defined as:Reynolds number Re is dimensionless and given by Re = ρ v d / η, where d is a characteristThe terminal velocity v_t of a small sphere of radius r falling in a fluid of viscosity η