Home › NEET UG › Physics › System of Particles and Rotational Motion › Angular momentum L of a particle of mass m, posi…
Angular momentum L of a particle of mass m, position r and momentum p is:
AL = r + p
BL = r · p
CL = r × p
DL = p × r
Answer & Solution
Correct answer: C. L = r × p
1. By definition, L = r × p (cross product).
2. dL/dt = r × F = τ (torque about same origin).
3. p × r = −L; the order matters in a cross product.
_Source: NCERT Class 11 Physics Ch 6 §6.10 Angular Momentum_
Related questions
The radius of gyration k of a body about an axis is defined so that:Two bodies have the same angular momentum L. The one with the LARGER moment of inertia hasA wheel rolls without slipping with the centre of mass having velocity v. The instantaneouA solid sphere of mass M and radius R has moment of inertia about a diameter:A flywheel of moment of inertia 2 kg m² rotates at 60 rpm. The torque required to bring itAn ice skater spinning with arms outstretched pulls her arms in. Her angular speed:Total kinetic energy of a body rolling without slipping is:A solid disc and a hollow ring of the same mass and radius roll without slipping down the