alleryTwo bodies of masses m₁ and m₂ have equal kinetic energies. The ratio of their momenta p₁/p₂ is:
Am₁ / m₂
Bm₂ / m₁
C√(m₁ / m₂)
D√(m₂ / m₁)
Answer & Solution
Correct answer: C. √(m₁ / m₂)
1. KE = p² / (2 m), so p = √(2 m K).
2. With equal K: p₁/p₂ = √(m₁ / m₂).
3. Heavier body has more momentum at the same KE — intuitive check.
_Source: syllabus Physics Ch 5, §5.4 (KE–momentum link)_
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