Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?
A5 times
B4 times
C3 times
D2 times
Answer & Solution
Correct answer: D. 2 times
1. Let Sunil's present age be x. Father's age = 3x more than Sunil = 4x (three times more than means 3x + x).
2. After 8 years: father 4x+8 = 2.5(x+8) → 4x+8 = 2.5x+20 → 1.5x = 12 → x = 8. So Sunil 8, Father 32.
3. After 16 years from now: Sunil 24, Father 48; ratio 48:24 = 2 times.
_Source: KMAT Karnataka 2021 PYQ Q.31_
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