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The work done by a constant force F in displacement d is
AF × d
BF · d
C|F| |d|
DF + d
Answer & Solution
Correct answer: B. F · d
1. Work = (component of F along d) × |d| = |F| cos θ × |d|.
2. This is exactly the scalar (dot) product F · d.
3. Hence work done = F · d.
_Source: Maharashtra Balbharati Std XII Mathematics Part 1, Ch 5 "Vectors" §5.4_
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