From the product schedule, total product is 600 units at 6 workers and 670 units at 7 workers. The average product at 7 workers is approximately:

1. Average product is total product divided by units of the variable factor: $AP = \frac{TP}{L}$. 2. At 7 workers, $TP = 670$. 3. So $AP = \frac{670}{7} \approx 95.7$ units. 4. The marginal product of the 7th worker is $670 - 600 = 70$, which is the AP value of a different worker count, so 70 is a trap; the AP is about 95.7 units. _Source: ICAI BoS CA Foundation Paper 4 Business Economics, Ch 3 Unit I "Theory of Production", p.17_