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In a homologous series, by what mass does each member differ from the one before it?
A12 amu
B14 amu
C16 amu
D28 amu
Answer & Solution
Correct answer: B. 14 amu
1. Successive members of a homologous series differ by one methylene (–CH₂) group.
2. A –CH₂ unit has mass = 12 (C) + 2(1) (H) = 14 amu.
3. So each member differs from the next by 14 amu, not 12, 16 or 28.
4. Hence the difference is 14 amu.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 11 "Carbon and its Compounds", p.166_
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