Home › Tamil Nadu SSLC (Class 10) › Chemistry › Solutions › The solubility of sodium nitrate is 114 g at 50 …
The solubility of sodium nitrate is 114 g at 50 degrees Celsius and 96 g at 30 degrees Celsius (per 100 g water). How much salt is thrown out when a saturated solution containing 50 g of water is cooled from 50 to 30 degrees Celsius?
A57 g
B18 g
C48 g
D9 g
Answer & Solution
Correct answer: D. 9 g
1. Salt dissolved in 50 g water at 50 degrees Celsius = (114 x 50) / 100 = 57 g.
2. Salt dissolved in 50 g water at 30 degrees Celsius = (96 x 50) / 100 = 48 g.
3. On cooling, the excess salt crystallises out: 57 - 48 = 9 g.
4. So 9 g is thrown out; 57 g and 48 g are the dissolved amounts before subtracting, not the crystallised mass.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 9 Solutions "Problems Based on Solubility", p.138_
Related questions
The mass of NaOH (M = 40 g/mol) required to prepare 500 mL of a 0.20 M NaOH solution isWhich of these solutions will boil at the highest temperature at 1 atm?The molality of a 1 M aqueous NaCl solution (density = 1.04 g/mL, NaCl M = 58.5 g/mol) is Osmotic pressure π of a dilute solution obeys π = C R T. Here C representsVan't Hoff factor i > 1 for a solute indicatesA negative deviation from Raoult law is expected whenIf a solute dimerises in solution, its observed molar mass compared with the calculated vaWhich of the following is NOT a colligative property?