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If 1.5 g of a solute dissolves in 15 g of water to form a saturated solution at 298 K, what is the solubility of the solute at this temperature?
A1.0 g per 100 g water
B15 g per 100 g water
C10 g per 100 g water
D22.5 g per 100 g water
Answer & Solution
Correct answer: C. 10 g per 100 g water
1. Solubility equals mass of solute divided by mass of solvent, multiplied by 100.
2. Substitute the values: (1.5 / 15) x 100.
3. 1.5 / 15 = 0.1, and 0.1 x 100 = 10.
4. So the solubility is 10 g per 100 g of water; the value 22.5 ignores the per-100 g basis.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 9 Solutions "Problems Based on Solubility", p.138_
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