A specimen emits 3.7 x 10^3 GBq per second. Expressed in curie, this activity equals (1 curie = 3.7 x 10^10 Bq)

1. Note the data: activity $3.7\times10^{3}\,\text{GBq}$, and 1 curie $= 3.7\times10^{10}\,\text{Bq}$. 2. Convert GBq to Bq: $3.7\times10^{3}\,\text{GBq} = 3.7\times10^{3}\times10^{9} = 3.7\times10^{12}\,\text{Bq}$. 3. Divide the activity by 1 curie in Bq. 4. Activity $= \dfrac{3.7\times10^{12}}{3.7\times10^{10}} = 10^{2}$. 5. So the activity is 100 curie. 6. Trap B (10) drops one power of ten; trap D (1000) adds an extra power of ten. _Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 6 Nuclear Physics "Nuclear Physics", p.92_