An electric bulb is rated 60 W at 220 V. What current does it draw when operating normally?

1. Electrical power is $P = VI$, so $I = \dfrac{P}{V}$. 2. Substitute $P = 60\,\text{W}$ and $V = 220\,\text{V}$. 3. $I = \dfrac{60}{220} \approx 0.27\,\text{A}$. 4. The value 13.2 wrongly divides V by P instead of P by V. _Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 4 Electricity "Electricity", p.62_