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A person experiences a state of weightlessness in a lift when the lift
AMoves up with acceleration equal to g
BStays at rest at one floor
CFalls down freely with acceleration equal to g
DMoves up at a steady speed
Answer & Solution
Correct answer: C. Falls down freely with acceleration equal to g
1. Apparent weight is R = m(g − a) for a downward acceleration a.
2. In free fall, a equals g, so R = m(g − g) = 0.
3. Zero apparent weight is the state of weightlessness.
4. Rule out option B: at rest a = 0, so R = mg, the full actual weight.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 1 "Laws of Motion", p.18_
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