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At what height from the centre of the Earth (radius R) does the acceleration due to gravity become one-fourth of its surface value?

A4R
BR/2
C2R
DR/4
Answer & Solution
Correct answer: C. 2R
1. Since g is proportional to 1/r², g'/g = R²/r'², where r' is the distance from the centre. 2. Set g' = g/4: then 1/4 = R²/r'², so r'² = 4R². 3. Taking the root, r' = 2R from the centre of the Earth. 4. Rule out 4R: that would make g'/g = 1/16, not 1/4. 5. Rule out R/2: a smaller radius gives a larger g, not a quarter. _Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 1 "Laws of Motion", p.19_
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