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On the surface of the Earth, the value of acceleration due to gravity g is
AMaximum at the equator and minimum at the poles
BThe same at all points on the surface
CGreatest at the centre of the Earth
DMaximum at the poles and minimum at the equator
Answer & Solution
Correct answer: D. Maximum at the poles and minimum at the equator
1. Since g is proportional to 1/R², g is larger where the radius is smaller.
2. The Earth's radius is smallest at the poles and largest at the equator.
3. So g is maximum at the poles and minimum at the equator.
4. Rule out option C: g is zero, not greatest, at the centre of the Earth.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 1 "Laws of Motion", p.17_
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