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A ball of mass 1 kg moving at 10 m s⁻¹ hits a floor and rebounds with the same speed after an elastic collision. What is the magnitude of the change in its linear momentum?
A20 kg m s⁻¹
B10 kg m s⁻¹
C0 kg m s⁻¹
D100 kg m s⁻¹
Answer & Solution
Correct answer: A. 20 kg m s⁻¹
1. Take the downward direction as positive: initial momentum = 1 x 10 = 10 kg m s⁻¹.
2. After rebound the velocity reverses, so final momentum = 1 x (−10) = −10 kg m s⁻¹.
3. Change Δp = final − initial = −10 − 10 = −20, magnitude 20 kg m s⁻¹.
4. Rule out 0: speed is unchanged but direction reverses, so momentum does change.
5. Rule out 10: that ignores the reversal and uses only one velocity.
_Source: Samacheer Kalvi (TN SCERT) Class 10 Science, Unit 1 "Laws of Motion", p.21_
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