Given the Moon's mass $7.34 \times 10^{22}$ kg, radius $1.74 \times 10^6$ m and $G = 6.67 \times 10^{-11}$ N m$^2$/kg$^2$, the escape velocity from the Moon is about:

1. Use $v_{esc} = \sqrt{\dfrac{2GM}{R}}$. 2. Numerator $2GM = 2\times6.67\times10^{-11}\times7.34\times10^{22} = 9.79\times10^{12}$. 3. Divide by $R = 1.74\times10^6$: $\dfrac{9.79\times10^{12}}{1.74\times10^6} = 5.63\times10^6$. 4. $v_{esc} = \sqrt{5.63\times10^6} \approx 2.37\times10^3$ m/s $= 2.37$ km/s. 5. 11.2 km/s is the Earth's escape velocity, so it is the trap. _Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 1 "Gravitation", p.23_