Maharashtra SSC (Class 10) Gravitation — practice questions
45 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice Maharashtra SSC (Class 10) Gravitation in the app →Who formulated the universal law of gravitation and mathematically derived Kepler's laws of planetary motion?A force that acts on an object moving along a circle and is always directed towards the centre of the circle iWhen the string of a whirling stone is suddenly released, the stone flies off in which direction?According to Kepler's first law, the orbit of a planet is:Kepler's second law states that the line joining a planet and the Sun sweeps out:Kepler's third law relates the period of revolution $T$ and the mean distance $r$ of a planet from the Sun as:The gravitational force between two objects is directly proportional to:In the gravitational force law $F = G\dfrac{m_1 m_2}{d^2}$, the quantity $G$ is best described as:What is the value of the universal gravitational constant $G$ in SI units, as first measured experimentally byIf the distance between two objects is doubled while their masses stay the same, the gravitational force betweUsing Kepler's third law $\dfrac{T^2}{r^3} = K$, the centripetal force on a planet in a circular orbit was shoA planet of mass $m$ moves in a circular orbit of radius $r$ with period $T$. The orbital speed of the planet Two persons of masses 75 kg and 80 kg sit 1 m apart. Taking $G = 6.67 \times 10^{-11}$ N m$^2$/kg$^2$, the graTaking $G = 6.67 \times 10^{-11}$ N m$^2$/kg$^2$, Earth's mass $6 \times 10^{24}$ kg and radius $6.4 \times 10The expression for the acceleration due to gravity $g$ on the surface of the Earth in terms of its mass $M$ anUsing $g = \dfrac{GM}{R^2}$ with $G = 6.67 \times 10^{-11}$ N m$^2$/kg$^2$, $M = 6 \times 10^{24}$ kg and $R =Two objects of different masses are dropped from the same height and fall freely. The acceleration due to gravOn the Earth's surface, at which location is the value of $g$ the highest?As we go to greater depths inside the Earth, the value of $g$:The value of acceleration due to gravity on the surface of the Moon is approximately:Which statement correctly distinguishes mass from weight?Taking $g = 9.8$ m/s$^2$, the weight of an object of mass 75 kg on the Earth's surface is:If you stand on a tall ladder so that your distance from the Earth's centre becomes $2R$, your weight becomes An object weighs 750 N on Earth. The Moon's mass is 1/81 of Earth's and its radius is 1/3.7 of Earth's. The obAn object is said to be in free fall when it moves under the influence of:True free fall, in which all objects reach the ground at the same time regardless of mass, is possible only:For an object thrown vertically upward, the acceleration due to gravity is taken as $-g$ because:An iron ball is released from rest from a height of 125 m and falls freely. Taking $g = 10$ m/s$^2$, the time A ball is released from rest and falls freely for 5 s. Taking $g = 10$ m/s$^2$, its velocity on reaching the gA tennis ball thrown vertically upward reaches a maximum height of 4.05 m. Taking $g = 10$ m/s$^2$, its initiaThe maximum height $s$ reached by a ball thrown vertically upward with initial velocity $u$ (taking magnitude The gravitational potential energy of an object of mass $m$ at a height $h$ above the Earth's surface (mass $MThe approximate formula $mgh$ for gravitational potential energy can be used only when:Escape velocity is the minimum initial velocity with which an object must be projected upward so that it:Using conservation of energy, the escape velocity from a body of mass $M$ and radius $R$ is:The escape velocity from the surface of the Earth is approximately:Given the Moon's mass $7.34 \times 10^{22}$ kg, radius $1.74 \times 10^6$ m and $G = 6.67 \times 10^{-11}$ N mAstronauts and objects inside an orbiting spacecraft appear weightless mainly because:An object takes 5 s to fall to the ground from a height of 5 m on a certain planet, starting from rest. The vaAn object's mass and weight on Earth are 5 kg and 49 N. Taking the Moon's $g$ as 1/6th of Earth's, its mass anAn object thrown vertically upward reaches a height of 500 m. Taking $g = 10$ m/s$^2$, its initial velocity waA ball falls off a table and reaches the ground in 1 s. Taking $g = 10$ m/s$^2$, its speed on reaching the groEarth's mass is $6 \times 10^{24}$ kg and the Moon's is $7.4 \times 10^{22}$ kg, separated by $3.84 \times 10^Earth's mass is $6 \times 10^{24}$ kg and its distance from the Sun is $1.5 \times 10^{11}$ m. If the gravitatA planet has period $T$ at distance $R$ from a star. Using Kepler's third law, its period at distance $2R$ wou