Home › Maharashtra SSC (Class 10) › Physics › Gravitation › Taking $g = 9.8$ m/s$^2$, the weight of an objec…
Taking $g = 9.8$ m/s$^2$, the weight of an object of mass 75 kg on the Earth's surface is:
A7.65 N
B75 N
C9.8 N
D735 N
Answer & Solution
Correct answer: D. 735 N
1. Weight is the gravitational force, $W = mg$.
2. Substitute $m = 75$ kg and $g = 9.8$ m/s$^2$.
3. $W = 75 \times 9.8 = 735$ N.
4. 75 is the mass in kg, not the weight; 9.8 N is the weight of just 1 kg, so both are traps.
_Source: Balbharati (Maharashtra Board) Class 10 Science & Technology, Ch 1 "Gravitation", p.18_
Related questions
Cavendish's torsion balance experiment (1798) measuredThe gravitational field near Earth's surface is approximately uniform becauseNewton showed that the same law that makes an apple fall to the ground alsoFor a body in a circular orbit around Earth of radius r, the ratio of kinetic energy to toThe weight of an object at a certain height above Earth's surface equals its weight at depThe variation of g with depth d below Earth's surface (assuming uniform density) isA geostationary satellite orbits Earth at a height where its period equalsThe gravitational potential energy of two point masses m₁ and m₂ separated by distance r i