In KMnO₄, the oxidation state of Mn is:
A+5
B+4
C+7
D+6
Answer & Solution
Correct answer: C. +7
K(+1) + Mn(x) + 4O(−2) = 0 → 1 + x − 8 = 0 → x = **+7**. KMnO₄ is the most common +7 Mn compound, a powerful oxidising agent.
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