Home › JEE Main › Chemistry › d and f Block Elements › Magnetic moment of [Fe(H₂O)₆]³⁺ (Fe³⁺ is d⁵, wea…
Magnetic moment of [Fe(H₂O)₆]³⁺ (Fe³⁺ is d⁵, weak field H₂O → high spin):
A2.83 BM
B0 BM
C5.92 BM (5 unpaired)
D1.73 BM
Answer & Solution
Correct answer: C. 5.92 BM (5 unpaired)
Fe³⁺: d⁵. H₂O is weak field → high spin: t₂g³ e_g², 5 unpaired electrons. μ = sqrt(35) = 5.92 BM.
Related questions
Magnetic susceptibility of Fe³⁺ vs Fe²⁺ in high-spin complexes:Why is Sc³⁺ colorless?Eu²⁺ is more stable than other Ln²⁺ because:Number of unpaired electrons in [Mn(CN)₆]³⁻ (Mn(III), d⁴, strong field CN⁻):Oxidation state of Cu in [Cu(NH₃)₄]²⁺:Coordination number of Ag in [Ag(CN)₂]⁻:K₂Cr₂O₇ (potassium dichromate) is a strong:Magnetic moment of complex with 5 unpaired d-electrons (high spin):