The electronic configuration of Cr (Z = 24) is:
A[Ar] 3d³ 4s³
B[Ar] 3d⁵ 4s¹
C[Ar] 3d⁶ 4s⁰
D[Ar] 3d⁴ 4s²
Answer & Solution
Correct answer: B. [Ar] 3d⁵ 4s¹
**Cr: [Ar] 3d⁵ 4s¹** (not 3d⁴ 4s²).
The half-filled 3d⁵ + half-filled 4s¹ configuration provides **extra stability** from exchange energy and symmetry.
**Similar exception in Cu:** 3d¹⁰ 4s¹ (not 3d⁹ 4s²).
Keep practising d- and f-Block Elements
Browse all d- and f-Block Elements questions for AP Intermediate 2nd Year, or explore more Chemistry topics.
Related questions
Why is Sc³⁺ colorless?Eu²⁺ is more stable than other Ln²⁺ because:Number of unpaired electrons in [Mn(CN)₆]³⁻ (Mn(III), d⁴, strong field CN⁻):Magnetic moment of [Fe(H₂O)₆]³⁺ (Fe³⁺ is d⁵, weak field H₂O → high spin):Coordination number of Ag in [Ag(CN)₂]⁻:K₂Cr₂O₇ (potassium dichromate) is a strong:Magnetic moment of complex with 5 unpaired d-electrons (high spin):Which transition metal forms unstable highest oxidation state +7?