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In the Arrhenius plot of ln k versus 1/T, what does the slope of the straight line equal?
A-Ea/R
Bln A
C-Ea/2.303R
DEa/R
Answer & Solution
Correct answer: A. -Ea/R
1. Taking ln of the Arrhenius equation: $\ln k = -\dfrac{E_a}{R}\cdot\dfrac{1}{T} + \ln A$.
2. Comparing with $y = mx + c$, slope $= -\dfrac{E_a}{R}$.
3. The intercept is $\ln A$, so option B is the intercept, not the slope.
4. Option C is the slope of the log (base 10) plot, not the ln plot.
_Source: NCERT Class 12 Chemistry Ch 3 "Chemical Kinetics", p.19_
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