A conductor carries a steady current when a charge of 30 C passes through a given cross-section in 1.5 minutes. The current in the conductor is

1. For a steady current, $I = q/t$. 2. Convert time: $t = 1.5 \times 60 = 90\ \text{s}$. 3. $I = 30/90 = 0.33\ \text{A}$. 4. Option C (20 A) wrongly uses $t = 1.5\ \text{s}$; A divides further incorrectly. _Source: syllabus Physics Ch 3 "Current Electricity", p.1_