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Probability that a leap year has 53 Sundays is
A1/7
B2/7
C1/365
D5/7
Answer & Solution
Correct answer: B. 2/7
1. Leap year = 366 days = 52 weeks + 2 days.
2. The 2 extra days are consecutive; equally likely combinations: (Sun-Mon),(Mon-Tue),...,(Sat-Sun) -> 7 cases.
3. Pairs containing Sunday: (Sat-Sun) and (Sun-Mon) -> 2 cases.
4. P(53 Sundays) = 2/7.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.5_
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