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Two events A, B are mutually exclusive with P(A) = 0.3, P(B) = 0.4. Then P(A or B) is
A0.1
B0.7
C0.5
D0.12
Answer & Solution
Correct answer: B. 0.7
1. For mutually exclusive events, P(A or B) = P(A) + P(B).
2. P(A) + P(B) = 0.3 + 0.4.
3. = 0.7.
4. So P(A or B) = 0.7.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.9_
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