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Two dice are rolled. The probability of getting a sum of 7 is
A1/12
B1/6
C1/4
D1/9
Answer & Solution
Correct answer: B. 1/6
1. Total outcomes = 6 * 6 = 36.
2. Favourable pairs summing to 7: (1,6),(2,5),(3,4),(4,3),(5,2),(6,1).
3. That is 6 outcomes.
4. P(sum = 7) = 6/36 = 1/6.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.6_
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