alleryIf the rank correlation coefficient is 0.6 and number of pairs is 10, sum of squared rank differences equals
A72
B60
C55
D66
Answer & Solution
Correct answer: D. 66
1. Spearman: rs = 1 - 6 * Sum(d^2) / (n(n^2 - 1)).
2. n(n^2 - 1) = 10 * 99 = 990.
3. 0.6 = 1 - 6 * S / 990, so 6S/990 = 0.4 and 6S = 396.
4. S = 66.
_Source: ICAI BoS Foundation Paper 3, Ch 17 'Correlation', p.8_
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