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Probability of getting at least one tail in 4 tosses of a fair coin is
A3/4
B7/8
C15/16
D1/16
Answer & Solution
Correct answer: C. 15/16
1. P(no tail in 4 tosses) = P(all heads) = (1/2)^4 = 1/16.
2. P(at least one tail) = 1 - P(no tail).
3. = 1 - 1/16.
4. = 15/16.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.10_
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