Two dice are rolled. P(sum >= 10) is
A1/12
B1/6
C5/36
D1/4
Answer & Solution
Correct answer: B. 1/6
1. Total outcomes = 36.
2. Favourable: sum 10 = (4,6),(5,5),(6,4) -> 3; sum 11 = (5,6),(6,5) -> 2; sum 12 = (6,6) -> 1.
3. Total favourable = 3 + 2 + 1 = 6.
4. P(sum >= 10) = 6/36 = 1/6.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.7_
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