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A box has 5 red and 4 green balls. Two are drawn at random without replacement. Probability both red is
A4/9
B10/81
C5/18
D5/9
Answer & Solution
Correct answer: C. 5/18
1. P(first red) = 5/9.
2. After removing one red, P(second red | first red) = 4/8 = 1/2.
3. P(both red) = (5/9) * (1/2).
4. = 5/18.
_Source: ICAI BoS Foundation Paper 3, Ch 15 'Probability', p.11_
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