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A man invests Rs.10000 partly at 8% SI and partly at 10% SI. Total interest after 1 year is Rs.880. Amount at 8% is
ARs.7000
BRs.4000
CRs.6000
DRs.5000
Answer & Solution
Correct answer: C. Rs.6000
1. Let x = amount at 8% and (10000 - x) at 10%; total = 1 year.
2. SI = 0.08x + 0.10(10000 - x) = 880.
3. 0.08x + 1000 - 0.10x = 880, so -0.02x = -120.
4. x = 6000.
_Source: ICAI BoS Foundation Paper 3, Ch 4 'Math of Finance', p.6_
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