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Solve (x + 2)/3 - (x - 1)/2 <= 1. Then x belongs to
A{x : x <= 1} only
B{x : x >= 1}
C{x : x >= -1} only
D{x : x <= -1} only
Answer & Solution
Correct answer: B. {x : x >= 1}
1. Multiply both sides by LCM 6: 2(x + 2) - 3(x - 1) <= 6.
2. Expand: 2 x + 4 - 3 x + 3 <= 6, so -x + 7 <= 6.
3. Subtract 7 and multiply both sides by -1 (flip sign): x >= 1.
4. So the solution is x >= 1.
_Source: Selina Concise Mathematics Class 10, Ch 4 Linear Inequations in One Variable (Mistral OCR'd PDF), section on fractional inequations_
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