Solve the double inequation 2 < x + 1 <= 5. Then x belongs to
A{x : 1 < x <= 4}
B{x : 2 <= x < 5} only
C{x : 0 < x <= 4} only
D{x : 3 < x <= 5} only
Answer & Solution
Correct answer: A. {x : 1 < x <= 4}
1. Subtract 1 from each part: 2 - 1 < x <= 5 - 1.
2. So 1 < x <= 4.
3. Lower bound is strict; upper bound is inclusive.
4. Hence option A is correct.
_Source: Selina Concise Mathematics Class 10, Ch 4 Linear Inequations in One Variable (Mistral OCR'd PDF), section on double inequations_
Keep practising Algebra: Equations, Inequations & Matrices
Browse all Algebra: Equations, Inequations & Matrices questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
The smallest natural number that satisfies x > 4 isA linear inequation in one variable can be written asSolve x + 3 > 5, then x belongs toSolve (2 x - 5) / 3 >= 1 over integers.Solve -2 (x - 3) <= 4. Then x belongs toSolve 2 x + 5 > 11, then x belongs toSolve (x + 2)/3 - (x - 1)/2 <= 1. Then x belongs toThe largest integer x satisfying 3 x - 4 < 2 x + 5 is