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Solve the double inequation 2 < x + 1 <= 5. Then x belongs to
A{x : 1 < x <= 4}
B{x : 2 <= x < 5} only
C{x : 0 < x <= 4} only
D{x : 3 < x <= 5} only
Answer & Solution
Correct answer: A. {x : 1 < x <= 4}
1. Subtract 1 from each part: 2 - 1 < x <= 5 - 1.
2. So 1 < x <= 4.
3. Lower bound is strict; upper bound is inclusive.
4. Hence option A is correct.
_Source: Selina Concise Mathematics Class 10, Ch 4 Linear Inequations in One Variable (Mistral OCR'd PDF), section on double inequations_
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