Home › ICSE Class 10 › mathematics › Arithmetic Progression › First negative term of the AP 121, 117, 113, ...…
First negative term of the AP 121, 117, 113, ... is the
A30th term
B32nd term
C31st term
D33rd term
Answer & Solution
Correct answer: B. 32nd term
1. a = 121 and d = -4.
2. Set 121 + (n - 1)(-4) < 0 gives n - 1 > 30.25.
3. Smallest integer n is 32.
4. So the 32nd term is the first negative.
_Source: Selina Concise Mathematics Class 10, Ch on Arithmetic Progression (Mistral OCR'd PDF), section on negative term_
Related questions
Rupees 720 was divided among A, B, C, D and E. The amounts received were in ascending ordeIf S_n = n^2 + 3 n, then first term and common difference areHow many three-digit numbers are divisible by 6?If sum of an AP is 100 and a = 5, l = 15, number of terms isIf a_n = 3 n + 5, the first three terms areSum of all natural numbers between 100 and 200 divisible by 7 isMiddle term of the AP 1, 5, 9, ..., 49 isSum of an AP with first term 7, last term 47 and 9 terms is