The area of a rectangle is 60 sq cm and length exceeds breadth by 4 cm. Breadth is
A10 cm
B5 cm
C8 cm
D6 cm
Answer & Solution
Correct answer: D. 6 cm
1. Let breadth be b; length = b + 4.
2. Area: b(b + 4) = 60, i.e. b^2 + 4b - 60 = 0.
3. Factor: (b - 6)(b + 10) = 0, take positive b = 6.
4. So breadth is 6 cm.
_Source: Selina Concise Mathematics Class 10, Ch 5 Quadratic Equations (Mistral OCR'd PDF), section on word problems_
Keep practising Quadratic Equations
Browse all Quadratic Equations questions for Andhra Pradesh SSC (Class 10), or explore more Mathematics topics.
Related questions
Solve by completing the square: x^2 + 6x + 5 = 0. Roots areIf alpha and beta are roots of x^2 - 7x + 10 = 0, then alpha + beta + alpha*beta equalsA train covers 360 km at uniform speed. If the speed were 5 km/h more, it would take 1 houThe product of two consecutive positive odd numbers is 143. The numbers areIf one root of x^2 - 6x + k = 0 is 2, then k equalsThe sum of squares of two consecutive positive integers is 113. The integers areFor what k does x^2 + kx + 9 = 0 have equal roots?Solve by quadratic formula: x^2 - 4x - 5 = 0. Roots are