Home › ICSE Class 10 › Mathematics › Quadratic Equations › The sum of squares of two consecutive positive i…
The sum of squares of two consecutive positive integers is 113. The integers are
A6 and 7
B7 and 8
C8 and 9
D5 and 6
Answer & Solution
Correct answer: B. 7 and 8
1. Let the integers be x and x + 1.
2. x^2 + (x + 1)^2 = 113 gives 2x^2 + 2x + 1 = 113.
3. Simplify: x^2 + x - 56 = 0, factor (x - 7)(x + 8) = 0.
4. Positive root x = 7, so integers are 7 and 8.
_Source: Selina Concise Mathematics Class 10, Ch 5 Quadratic Equations (Mistral OCR'd PDF), section on word problems_
Related questions
The study of inequalities is described as useful in solving problems in science and:A firm needing at least 6 units and at most 10 would write that as a:Which sign makes a statement an inequality rather than an equation?Unless stated otherwise, inequalities in that chapter are solved over the set of:The set of all values of the variable that make an inequality true is called its:Solving 4x plus 3 less than 6x plus 7 gives:When x is a real number in that inequality, the solution set is written as:When x is an integer in that inequality, the largest solution is: