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The sum of squares of two consecutive positive integers is 113. The integers are
A6 and 7
B7 and 8
C8 and 9
D5 and 6
Answer & Solution
Correct answer: B. 7 and 8
1. Let the integers be x and x + 1.
2. x^2 + (x + 1)^2 = 113 gives 2x^2 + 2x + 1 = 113.
3. Simplify: x^2 + x - 56 = 0, factor (x - 7)(x + 8) = 0.
4. Positive root x = 7, so integers are 7 and 8.
_Source: Selina Concise Mathematics Class 10, Ch 5 Quadratic Equations (Mistral OCR'd PDF), section on word problems_
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