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Probability of any event satisfies:

A0 ≤ P ≤ 1
B0 ≤ P ≤ 100
C−1 ≤ P ≤ 1
DP ≥ 1
Answer & Solution
Correct answer: A. 0 ≤ P ≤ 1
The probability of an event $E$, denoted as $P(E)$, is defined as the ratio of the number of favorable outcomes to the total number of outcomes in a sample space. 1. **Minimum Value**: The smallest number of favorable outcomes is $0$ (this happens when the event is impossible). Therefore, the minimum probability is: $$P(E) = \frac{0}{n} = 0$$ 2. **Maximum Value**: The largest number of favorable outcomes is equal to the total number of outcomes $n$ (this happens when the event is certain). Therefore, the maximum probability is: $$P(E) = \frac{n}{n} = 1$$ 3. **Conclusion**: Since the number of favorable outcomes $m$ must satisfy $0 \leq m \leq n$, it follows that dividing by $n$ gives: $$\frac{0}{n} \leq \frac{m}{n} \leq \frac{n}{n}$$ $$0 \leq P(E) \leq 1$$ Thus, the probability of any event must be between 0 and 1, inclusive.
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