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Force on a current-carrying conductor in a magnetic field equals:

AF = m a
BF = V I
CF = B I L
DF = Q V
Answer & Solution
Correct answer: C. F = B I L
The force experienced by a current-carrying conductor placed in a magnetic field is a result of the interaction between the external magnetic field and the magnetic field generated by the current itself. ### 1. Variables Definition - $F$: The magnetic force (Newtons, $N$) - $B$: The magnetic flux density or magnetic field strength (Tesla, $T$) - $I$: The electric current flowing through the conductor (Amperes, $A$) - $L$: The length of the conductor inside the magnetic field (Meters, $m$) ### 2. The Formula The magnitude of the force is given by the equation: $$F = B I L \sin(\theta)$$ Where $\theta$ is the angle between the direction of the current and the direction of the magnetic field. ### 3. Conclusion When the conductor is perpendicular to the field ($\theta = 90^\circ$), $\sin(90^\circ) = 1$, and the formula simplifies to: $$F = B I L$$ This matches option C.
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