Force on a current-carrying conductor in a magnetic field equals:
AF = m a
BF = V I
CF = B I L
DF = Q V
Answer & Solution
Correct answer: C. F = B I L
The force experienced by a current-carrying conductor placed in a magnetic field is a result of the interaction between the external magnetic field and the magnetic field generated by the current itself.
### 1. Variables Definition
- $F$: The magnetic force (Newtons, $N$)
- $B$: The magnetic flux density or magnetic field strength (Tesla, $T$)
- $I$: The electric current flowing through the conductor (Amperes, $A$)
- $L$: The length of the conductor inside the magnetic field (Meters, $m$)
### 2. The Formula
The magnitude of the force is given by the equation:
$$F = B I L \sin(\theta)$$
Where $\theta$ is the angle between the direction of the current and the direction of the magnetic field.
### 3. Conclusion
When the conductor is perpendicular to the field ($\theta = 90^\circ$), $\sin(90^\circ) = 1$, and the formula simplifies to:
$$F = B I L$$
This matches option C.
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