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A straight conductor of length 0.5 m carries 2 A at right angles to a 0.4 T magnetic field. The force on it is:
A0.04 N
B40 N
C4 N
D0.4 N
Answer & Solution
Correct answer: D. 0.4 N
1. The force on a current-carrying conductor in a magnetic field is F = B·I·L·sin θ.
2. The angle between current and field is 90°, so sin θ = 1.
3. Substitute the given values: F = 0.4 × 2 × 0.5 × 1.
4. F = 0.4 N.
5. Option A is off by a factor of ten; C and D overshoot by powers of ten.
6. So the correct force is 0.4 N.
_Source: NCERT Class 10 Science Ch 13 'Magnetic Effects of Electric Current' (learncbse.in extract)_
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