Beryllium fluoride has just two regions of electron density around the central atom. VSEPR predicts a bond angle of:
A180 degrees
B360 degrees
C90 degrees
D109.5 degrees
Answer & Solution
Correct answer: A. 180 degrees
1. Two regions repel each other and want maximum separation.
2. On a sphere, the furthest two points sit directly opposite.
3. That gives a linear molecule, so 180 degrees.
_Source: OpenStax Chemistry 2e, Chapter 7, Chemical Bonding and Molecular Geometry._
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