White light (400–700 nm) passes through a glass of refractive index 1.55. The wavelength range observed in the glass becomes approximately:
A400–700 nm
B258–451 nm
C620–1085 nm
DCannot be determined
Answer & Solution
Correct answer: B. 258–451 nm
$\lambda_{glass} = \lambda_0/n$. So 400/1.55 ≈ 258 nm and 700/1.55 ≈ 451 nm. Wavelengths shorten in proportion.
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