For which value of n does $6^n$ end with the digit zero?

Question

Accepted Answer

D. No natural number n works

A number ends with 0 only if its prime factorisation contains both 2 AND 5. 6^n = (2 × 3)^n = 2^n × 3^n.
The prime 5 never appears, so 6^n never ends in zero, no matter how large n is.

Answer

For n = 1 only

Answer

For n = 2 and higher

Answer

Only for n = 5

For which value of n does $6^n$ end with the digit zero?

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