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For which value of n does $6^n$ end with the digit zero?
AFor n = 1 only
BFor n = 2 and higher
COnly for n = 5
DNo natural number n works
Answer & Solution
Correct answer: D. No natural number n works
A number ends with 0 only if its prime factorisation contains both 2 AND 5. 6^n = (2 × 3)^n = 2^n × 3^n. The prime 5 never appears, so 6^n never ends in zero, no matter how large n is.
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