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Nitration of toluene (methylbenzene) on the lab gives products mostly at:
AMeta positions only, since -CH$_3$ is meta directing here
BOnly the carbon bearing the methyl group itself in the ring
CAll positions equally, since toluene loses the directing effect
DOrtho and para positions, since -CH$_3$ is ortho/para directing
Answer & Solution
Correct answer: D. Ortho and para positions, since -CH$_3$ is ortho/para directing
Methyl group is activating, ortho/para directing on the benzene ring.
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