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Adding HBr to propene CH$_3$-CH=CH$_2$ in absence of peroxide gives mainly:
A1-bromopropane, anti-Markovnikov product on the bench
B2-bromopropane, by Markovnikov's rule on the alkene
C3-bromopropane, neither end nor middle in the chain
DNo reaction, since HBr does not add to alkenes ever
Answer & Solution
Correct answer: B. 2-bromopropane, by Markovnikov's rule on the alkene
Markovnikov: H adds to terminal CH$_2$ (more H), Br adds to middle CH (fewer H), giving 2-bromopropane.
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