Benzene satisfies Hückel's rule with $4n + 2$ pi electrons for $n =$:
A$1$, since 6 pi electrons matches $4\cdot 1 + 2 = 6$
B$0$, since the smallest case gives only 2 pi electrons
C$2$, since 10 pi electrons would be needed for benzene
D$3$, since 14 pi electrons appear in larger aromatic rings
Answer & Solution
Correct answer: A. $1$, since 6 pi electrons matches $4\cdot 1 + 2 = 6$
Benzene has 6 pi electrons; $4n + 2 = 6$ gives $n = 1$.
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