Practice free →
HomeJEE MainChemistryHydrocarbons › According to Hückel's rule, a planar cyclic comp…

According to Hückel's rule, a planar cyclic compound is aromatic if it has:

AAn odd number of double bonds
B$(4n+2) \pi$ electrons in a continuous conjugated system, with $n = 0, 1, 2, \ldots$
C$(4n+1) \pi$ electrons in a continuous conjugated system
D$4n \pi$ electrons
Answer & Solution
Correct answer: B. $(4n+2) \pi$ electrons in a continuous conjugated system, with $n = 0, 1, 2, \ldots$
**Hückel's rule**: a planar, fully conjugated, cyclic molecule is aromatic if and only if it has $(4n + 2)$ $\pi$ electrons, where $n$ is a non-negative integer. Examples: - Benzene: 6 $\pi$ electrons ($n=1$). Aromatic. - Naphthalene: 10 $\pi$ electrons ($n=2$). Aromatic. - Cyclobutadiene: 4 $\pi$ electrons (not $4n+2$). **Anti-aromatic**, highly unstable. - Cyclopropenyl cation: 2 $\pi$ electrons ($n=0$). Aromatic. Aromaticity gives extra stability (resonance stabilisation energy) and shifts properties: NMR ring current, no addition reactions at room temperature, etc.
Solve this in the app — JEE Main practice & 24k+ MCQs →
Related questions