Light enters a glass slab ($n = 1.5$) from air ($n = 1$) at angle of incidence $30^\circ$. The angle of refraction is approximately:
A$19.5^\circ$, by $\sin\theta_2 = (1/1.5)\sin 30^\circ$
B$45^\circ$, equal to twice the incidence angle here
C$30^\circ$, since refraction does not bend the ray ever
D$60^\circ$, twice the incidence, away from normal
Answer & Solution
Correct answer: A. $19.5^\circ$, by $\sin\theta_2 = (1/1.5)\sin 30^\circ$
$\sin\theta_2 = 0.5/1.5 = 0.333$, $\theta_2 \approx 19.5^\circ$.
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