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Two resistors $3\ \Omega$ and $6\ \Omega$ are connected in parallel. The equivalent resistance is:
A$9\ \Omega$, the simple sum of the two resistors
B$2\ \Omega$, since $1/R = 1/3 + 1/6 = 1/2$
C$0.5\ \Omega$, the inverse of the parallel sum
D$18\ \Omega$, the product of the two values
Answer & Solution
Correct answer: B. $2\ \Omega$, since $1/R = 1/3 + 1/6 = 1/2$
$1/R = 1/3 + 1/6 = 1/2$; $R = 2\ \Omega$.
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