A simple pendulum's length is increased four times. Its period changes by a factor of:
A$4$, since period scales with length linearly
B$1/2$, since longer pendulums swing faster on the wall
C$1/4$, the inverse of the length factor here
D$2$, since $T \propto \sqrt{L}$ by the pendulum formula
Answer & Solution
Correct answer: D. $2$, since $T \propto \sqrt{L}$ by the pendulum formula
$T \propto \sqrt L$; multiplying $L$ by 4 multiplies $T$ by 2.
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